SPAM THREAD!

[Robert the small]

The only thing wierder then a 4chan game? A 2chan one, no less.

[Jesuszilla]

http://www.youtube.com/watch?v=d83RQu8uoWo

[Deleted User]

[Jesuszilla]

It has arrived.














Mandatory boob shot:



We need the spoiler tags back.

[Robert the small]

Lucky you, all of the game stores by me are Libareache gay and don't have it yet.

[Jesuszilla]

Liberace, and yeah, same here. That's why I ordered on Amazon.

[UHMEEEEBA]

What the fucking shit?

[Jesuszilla]

Isn't Marx from Kirby Superstar?


JANGO, I DEMAND YOU CONVERT MARX

[Karasawa]

[Jango]

JANGO, I DEMAND YOU CONVERT MARX

Oh god, that's going to take a lot of effort, and the random tiles that randomly appear in his wings is going to be a pain in the ass.

[UHMEEEEBA]

YOU ARE A BEARDED ****ER!

[ughwtf]

AN GUITAR HERO III
http://img20.imageshack.us/img20/9334/bupabunengzaixiangjianmq5.swf

[Jesuszilla]

YO NEON


Any idea how to solve for x and z in this equation? Assume w and y are given.


y = z ・e^{(w ・x)}

[UHMEEEEBA]

Can't remember the exact procedure for that right off the top of my head, and my book for this is miles away at school, sorry*.

That looks like an equation for exponential growth\decay though, but usually you'd be given x and solve for y by using initial conditions.

Here's some ideas though, you can rewrite the expression as,

y = z ・e^(w) ・e^(x)

and then,

(1/e^(w)) ・y = z ・e^(x)

Trying to use substition though won't work here, as you'll just end up with a tautology. If you had another equation relating x and z, or more information you could solve it, but it looks like you're missing something.

*Before you bitch at me to go get it, the floors are locked I couldn't if I wanted to.

[Jesuszilla]

x and z are the only things in that equation that are not given. Assume w = 1 as well.